Calendar

**Calendar tips and tricks**

**Calendar aptitude problems shortcuts method tips tricks **

This is one of the reasoning question frequently asked in all the examination. Basically the calendar questions asked to find the leap year, how many days in the year, if first day of month is Tuesday what is the next last day. Very simple calendar problems shortcuts is enough to solve this calendar aptitude question within a 3 minutes. The people who felt that this one is difficult to solve, please see the calendar aptitude tricks formula below and practice it to do well. Firstly we given the calendar problems shortcut methods formula, then some solved example are given. Not only that, at end of this post you will find useful calendar problems solving tricks video. But be true, practicing this calendar aptitude concepts frequently to become familiar with it, without practicing you can't do it faster in the exams.

**Important Calendar Aptitude formula :**

WEEK DAY : There are seven days in a week. A week starts with Monday and ends at Sunday.

After which again comes Monday. The same cycle goes on and on.

MONTHS OF THE YEAR : We know that, there are 12 months in a year. The months of the year with the number of the days in that month are given below.

1. JANUARY-31 7. JULY-31

2. FEBRUARY-28 OR 29 8. AUGUST-31

3. MARCH-31 9. SEPTEMBER-30

4. APRIL-30 10. OCTOBER-31

5. MAY-31 11. NOVEMBER-30

6. JUNE-30 12. DECEMBER-31

**Ordinary year** - Only 365 days are present in the Ordinary year.

**Odd days** - Some question date and month will be given. You have to find the day regarding the given date. For these type of questions you can use odd day concept. Odd day concept is nothing but in the given period of time, number days more than the complete week.

**Leap year** - A year which is divisible by 4, but it won't be century. But you have another option that every 4th century should be a leap year. It has 366 days.

February of a leap year has 29 days. so, there are 366 days in a leap year.

Thus, 1 leap year = 366 days = 52 weeks and 2 days. A leap year comes after every 4 years.

Century:- A block of 100 years is called a century. A century has, thus a total of 100 yr.

Thus, each one of the years 1500, 1700, 2200 is a century.

**Example for Leap year - **The years 2004, 1948 are leap years. 2001, 2007, 2005 are not a leap year.

**Counting odd days** -

**Rule 1** - Ordinary year = 365 days. It has 52 weeks plus 1 day. So ordinary years has 1 odd day.

**Rule 2 **- Leap year = 366 days. Totally 52 weeks plus 2 days. Leap year has two odd days.

**Rule 3 **- 50 years = 38 ordinary years + 12 leap years

Totally = (38x1 odd day) + 12x2 odd days)

Therefore 62 odd days, then separate it in to weeks.

So 8 weeks+ 6 odd days.

For 50 years there will be a 6 odd days.

**Calendar aptitude solve examples :**

1. Today is Monday. After 61 days, it will be:

(A) Wednesday (B) Saturday

(C) Tuesday (D) Thursday

**Answer : (B)**

**Explanation : **Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

∴ After 61 days, it will be Saturday.

2. Which of the following is not a leap year?

(A) 500 (B) 800

(C) 1600 (D) 2000

**Answer :** (**A)**

**Explanation : **The century divisible by 400 is a leap year.

∴ The year 500 is not a leap year.

3. January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?

(A) Monday (B) Tuesday

(C) Wednesday (D) Sunday

**Answer : (B)**

**Explanation : **The year 2007 is an ordinary year. So, it has 1 odd day.

1^{st} day of the year 2007 was Monday.

1^{st} day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.

4. If Asfaq’ birthday is on May 25 which is Monday and his sister’s birthday is on July 13. Which day of the week is his sister’s birthday?

(A) Monday (B) Wednesday

(C) Thursday (D) Friday

**Ans : (A)**

**Explanation :** Reference day : May 25th Monday

Days from May 25th to July 13 = 6 + 30 +13 = 49

No of odd days : 49/7 = 0